PoE calculator: line length and voltage drop
PoE power is lost to conductor resistance over twisted pair — the device receives less than the switch outputs, and on a long line a PoE camera or access point might not power up. Choose a PoE standard and conductor gauge (AWG) — the calculator estimates voltage drop, voltage at the device, and the maximum length.
Input data
Result
Fill in the fields — the verdict will appear here
An estimate based on DC copper conductor resistance at 20 °C; CCA (copper-clad aluminum) and heating cause greater losses. Maximum length is limited by both power and the data channel (100 m).
How it's calculated
- Loop resistance is taken from conductor gauge and length. In 802.3af/at, power runs over two pairs; in 802.3bt, over four, with conductors working in parallel.
- Voltage drop is the PoE current times this resistance; what's left at the device is the source voltage minus the loss.
- What remains must be enough for the chosen standard's minimum, and the channel length is capped at 100 m regardless.
Example: AWG 24, PoE+ (802.3at), 50 m → a 4.21 Ω loop, a 2.53 V drop, 47.5 V at the device against a minimum allowed 42.5 V.
| Gauge | Cross-section, mm² | Resistance, Ω/m |
|---|---|---|
| AWG 26 | 0.129 | 0.1345 |
| AWG 24 | 0.205 | 0.0842 |
| AWG 23 | 0.258 | 0.0668 |
| AWG 22 | 0.326 | 0.053 |
| Standard | Pairs used for power | Current, A | Source U, V | Minimum at device, V |
|---|---|---|---|---|
| 802.3af (PoE, 15.4 W) | 2 | 0.35 | 48 | 37 |
| 802.3at (PoE+, 30 W) | 2 | 0.6 | 50 | 42.5 |
| 802.3bt Type 3 (PoE++, 60 W) | 4 | 0.6 | 50 | 42.5 |
| 802.3bt Type 4 (90 W) | 4 | 0.96 | 52 | 41.1 |
ΔU = I·Rloop; PoE 802.3af/at — 2 pairs (Rloop = Rcond·L), 802.3bt — 4 pairs (Rcond·L/2). Channel length is capped at 100 m per ISO/IEC 11801 and GOST R 53246.
This is an estimate
Verify final values against current standards, the project design, and equipment nameplates.